Woo! Made an indentation grammar! Kinda!

main
Shoofle 11 years ago
parent dff49a1cce
commit 96ec8b6319
  1. 30
      articles/text_editors_with_contenteditable.article.html

@ -174,4 +174,34 @@ identifier = letters:[A-Za-z]+ { return letters.join(""); }
whitespace = [ \n\t]* whitespace = [ \n\t]*
</code></pre> </code></pre>
<p>So, it nearly killed me, but I managed to figure out how to make a parser (using pegjs) that <em>actually parses indentation-based grammars!</em> The basic way it works is that as it matches a line, it reads in the number of spaces before it. Using that, it figures out what indentation level it's at - then, as it's returning the line's payload, it puts the payload into the right code block. It's hacky and awful but I think I understand how it works. I'd rather move the logic into the <code>block</code> rule rather than the <code>line</code> rule, but that's pretty simple in theory. Here you go:
<pre><code>
{ var code = [];
var indentations = [0];
var current_head = [code]; }
b = line* { return code; }
line =
(spaces:" "* &amp;
{ var level = spaces.length;
if (level &gt; indentations[indentations.length-1]) {
indentations.push(level);
var new_block = [];
current_head[current_head.length-1].push(new_block);
current_head.push(new_block)
} else if (indentations.indexOf(level) == -1) {
return false;
} else {
while (indentations[indentations.length-1] != level) {
indentations.pop()
current_head.pop()
}
}
return true; }
{ return spaces.length; })
payload:("ab" bs:"b"+ "a" { return "ab" + bs.join("") + "a"; })
"\n"
{ current_head[current_head.length-1].push(payload);
return payload; }
</code></pre>
</article> </article>

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